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(2x^2)+27x-105=0
a = 2; b = 27; c = -105;
Δ = b2-4ac
Δ = 272-4·2·(-105)
Δ = 1569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{1569}}{2*2}=\frac{-27-\sqrt{1569}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{1569}}{2*2}=\frac{-27+\sqrt{1569}}{4} $
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